...之和输入2个正整数a和n,求a+aa+aaa+aa…a(n个a)之和。答:h>int main(void){ int a,n,i,sum,z=0,aa=0; printf("Input a,n: "); scanf("%d,%d",&a,&n); sum=0; for(i=1;i<=n;i++){ sum=10*sum+a; //这里循环节你错了 z=z+sum; } printf("s=%d",z); return 0; } ...
如何输入2个正整数a和n,计算a,aa,aaa,aa…a。例如,输入2和3,输出2...答:include<iostream> using namespace std;int main() { int a, n, i = 1, j = 1;cin >> a >> n;while (i <= n) { j = 1;while (j <= i)cout << a; ++j;if (i == n) cout << '\n';else cout << ',';++i;} return 0;} ...
输入两个正整数 a 和 n, 求a+aa+aaa+aa…a(n个a)之和。 定义并调用函数...答:long fn(int ,int);int main(){ int a, i, n;int ri, repeat;long sn;long fn(int a, int n);scanf("%d", &repeat);for(ri = 1; ri <= repeat; ri++){ scanf("%ld%d", &a, &n);sn=0;/*---*/for(i=0;i<n;i++){ sn=sn+fn(a,i);} printf("%ld", sn);...