...若能输出m与n的值,否则继续判断两个数的奇偶性,答:include<stdio.h> void main() { int m,n;scanf("%d%d",&m,&n);if ( m%n==0 ) printf("%d,%d\n",m,n);else { printf("%d: ",m); if ( m%2==0 ) printf("even\n"); else printf("odd\n");printf("%d: ",n); if ( n%2==0 ) printf("even\n"); else ...