第1个回答 2019-09-20
public class Yttt {
public static void main(String[] args) {
int n = 60;
int mult;
try{
mult = mult(n - 1, n);
}catch (Exception e){
mult = Integer.MAX_VALUE;
}
System.out.println(mult);
}
public static int mult(int n,int m){
if(n==0){
return 1;
}
int mult = mult(n - 1, n);
if(mult<0){
throw new RuntimeException("");
}
return mult*m;
}
}本回答被网友采纳