亲,需要的是二氧化碳
设需要二氧化碳xg,则有
Ca(OH)2 + CO2 = CaCO3(沉淀) + H2O
74g 44g
1.48g xg
74g/1.48g=44g/xg x=0.88g
答:需要二氧化碳0.88g。
追问74是谁下面的44又是谁下面的1.48又是谁下面的×
追答74是Ca(OH)2的相对原子质量=钙是40*1个+(氧是16+氢是1)*2个=74
44是CO2的相对分子质量=碳是12*1个+氧是16*2个=44
1.48是题目给你的氢氧化钙的质量啊,x是设的CO2的质量
明白了吗?
追问嗯
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/e61190ef76c6a7efc223e324fffaaf51f3de66ae?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/d31b0ef41bd5ad6e85912de883cb39dbb6fd3c43?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/a8014c086e061d9595cc7d3a79f40ad162d9ca2e?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/5882b2b7d0a20cf4de314bdd74094b36acaf990b?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/0824ab18972bd4076ad766ff79899e510fb3099b?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
最后一点
追答大哥啊,这是一点啊
回答个题目真的好难,好辛苦啊!
追问好嘛真的就这些了