c语言中如何利用%判定整数的奇偶性

Question

int n1=7,n2=2;float f1=7.0,f2=2.0;printf ("整数相除，得到商数：%d\n",n1/n2);printf ("整数求余，得到余数：%d\n\n",n1%n2);printf ("正负整数相除，得到商数：%d\n",(-n1)/n2);printf ("正负整数求余，得到余数：%d\n\n",(-n1)%n2);printf ("两个浮点数相除，得到商数：%f\n",f1/f2);printf ("浮点数除以整数，得到商数：%f\n",f1/n2);printf ("整数除以浮点数，得到商数：%f\n",n1/f2);

Answer 1

if(n%2==0)表示偶数！if(n%2!=0)表示奇数。#include<stdio.h>int main(){int n;printf("input n:");scanf("%d",&n);if(n%2==0)printf("%d是偶数!\n",n);else printf("%d是奇数!\n",n);return 0;}