机智的小伙伴们,求教这道题的详细做法,多谢啦

如题所述

第1个回答  2014-12-09
设边空为x,根据比例式边空:字宽:字距=9:6:2,得:字宽=6x/9,字距=2x/9;
18个字,有17个字距,2个边空,横标框总长12.8m,
则列式为:2边空+18字宽+17字距=12.8,
即:2x+18*(6x/9)+17*(2x/9)=12.8,
得边空x=0.72m;字宽=6x/9=0.48m;字距=2x/9=0.16m
也就是说,边空为0.72m,字宽为0.48m,字距为0.16m设边空为x,根据比例式边空:字宽:字距=9:6:2,得:字宽=6x/9,字距=2x/9;
18个字,有17个字距,2个边空,横标框总长12.8m,
则列式为:2边空+18字宽+17字距=12.8,
即:2x+18*(6x/9)+17*(2x/9)=12.8,
得边空x=0.72m;字宽=6x/9=0.48m;字距=2x/9=0.16m
也就是说,边空为0.72m,字宽为0.48m,字距为,0.16m
热心网友 2013-11-16