C语言，输入年月日，判断是这一年的第几天?

Question

如题所述

Answer 1

#include <stdio.h>
int main(void)
{
int year,month,day,sum,leap;
printf("请输入年月日，每个数据以空格相隔：");
scanf("%d %d %d", &year, &month, &day);
switch(month)
{
case 1:sum = 0;
break;
case 2:sum = 31;
break;
case 3:sum = 59;
break;
case 4:sum = 90;
break;
case 5:sum = 120;
break;
case 6:sum = 151;
break;
case 7:sum = 181;
break;
case 8:sum = 212;
break;
case 9:sum = 243;
break;
case 10:sum = 273;
break;
case 11:sum = 304;
break;
case 12:sum = 334;
break;
default:printf("月份数输入错误！\n");
return -1;
}
sum += day;
if (year%400==0 || (year%100!=0 && year%4==0))
leap = 1;
else
leap = 0;
if (1==leap && month>2)
sum++;
printf("这一天是这一年的第%d天\n", sum);
return 0;
}

Answer 2

main()
{
int year,moth,day;;
int mo[12]={31,28,31,30,31,30,31,31,30,31,30,31};
int d,i;
scnaf("%d %d %d",&year,&moth,&day);
d=day;
if(闰年判断)
mo[1]=29;
for(i=0;i<moth-1;i++)
d+=mo[i];
printf("%d",d);

}本回答被提问者和网友采纳

Answer 3

追问 case 1:sum=0;break; default:printf("data error");break; } sum=sum day; if(year@0==0||(year%4==0&&year 0!=0)) leap=1; else leap=0; if(leap==1&&month>2) sum ; printf("%d",sum); }

Answer 4

Answer 5

if(year%00==0