4分之Y+2减去6分之2Y-3等于1方程求解

Question

如题所述

Answer 1

(y + 2)/4 - (2y - 3)/6 = 13(y + 2) - 2(2y - 3) = 123y + 6 - 4y + 6 = 12y = 0

Answer 2

(y+2)/4-(2y-3)/6=16(y+2)-4(2y-3)=246y+12-8y+12=24-2y=0y=0

Answer 3

Y=0

Answer 4

等于零。