#include <reg51.h>
unsigned char led;
unsigned char LED_CODE[10] = { 0xC0,0xF9,0xA4,0xB0,0x99,0x92,0x82,0xF8,0x80,0x90 };
void main(void)
{
led = 0;
TMOD=0x10;
TH1=(65536-50000)/256;
TL0=(65536-50000)%256;
ET1=1;
EA=1;
TR1=1;
P2 = LED_CODE[led];
led++;
while(1);
}
//Timer1
void Timer1_Routine(void) interrupt 3
{
static unsigned char counter;
TH1=(65536-50000)/256;
TL0=(65536-50000)%256;
counter++;
if(counter == 20)
{
counter = 0;
P2 = LED_CODE[led];
led++;
if(led == 10)
led = 0;
}
}
请问,放在主函数中的
P2 = LED_CODE[led];
led++;
是什么意思?中断函数中不是已经有了么?
还有一点,
led = 0;
P2 = LED_CODE[led];
led++;
P2不是只接收到0的码么(因为觉得led++影响不了 LED_CODE[led])
为何接收到的是0到9的码。
谢谢。