两个定值电阻a、b分别为5欧姆、10欧姆并联后接在2.0v的电源两端，干路中的电流为多少

Question

如题所述

Answer 1

1/R = 1/5 + 1/10
1/R = 3/10
R = 10/3
I = U/R = 2/(10/3) = 3/5 = 0.6 (安)
答：干路中的电流为0.6安培。

Answer 2

解：∵并联
∴U=U1=U2=2.0v
R总=R1*R2/R1+R2=5欧姆*10欧姆/5欧姆+10欧姆=10/3欧姆
I=U/R=2.0v/（10/3欧姆）=0.6A
∴干路中的电流为0.6A

Answer 3

/R = 1/5 + 1/10
1/R = 3/10
R = 10/3
I = U/R = 2/(10/3) = 3/5 = 0.6 (安)
答：干路中的电流为0.6安培。