解ï¼è¿æ¥â³ABCçåå¿Oåâ³A1B1C1çåå¿O1ï¼CDãC1D1å为â³ABCãâ³A1B1C1çé«ï¼åOO1å³ä¸ºæ£ä¸æ£±å°çé«
C1O1=2C1D1/3=â3
CO=2CD/3=4â3
H=O1O=â[CC^2-(CO-C1O1)^2]=3
S1=Sâ³ABC=â3
S2=Sâ³A1B1C1=16â3
V=H(S1+â(S1S2)+S2)=3(12+17â3)=36+51â3
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