=â«(â(1+e^x)-â(1-e^x))/2e^xdx
=â«u/2(u²-1)dln(u²-1)-â«v/2(1-v²)dln(1-v²)
=â«u²/(u²-1)²du+â«v²/(1-v²)²dv
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â«u²/(u²-1)²du
=â«1/(u²-1)+1/(u²-1)²du
=1/2ln|(u-1)/(u+1)|+â«1/(tant)^4dsect
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=-â«csctdcott-â«(cotcsct+csc²t)/(cott+csct)dt
=-csctcott+â«cottdcsct+ln|cott+csct|
=(ln|cott+csct|-cottcsct)/2
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