第1个回答 2023-07-11
解:化简:
(√ab-ab)/(a+√ab)÷(√ab-a)/(a-b)
=(√ab-ab)/(a+√ab)×(a-b)/(√ab-a)
=[(√ab-ab)(a-b)]/[(a+√ab)(√ab-a)]
=[(√ab-ab)(a-b)]/(ab-a^2)
=[(√ab-ab)(a-b)]/[-a(a-b)]
=(√ab-ab)/(-a)
=b-√ab/a
∵a=(√3-√2)/(√2+√3)=5-2√6
b=5+2√6
∴原式=5+2√6-[√(5-2√6)×(5+2√6)]/(5-2√6)
=5+2√6-1/(5-2√6)
=5+2√6-(5+2√6)
=0