在C语言编程中，给出一个百分制成绩，要求输出成绩等级

Question

要求输出成绩等级A、B、C、D、E。90分以上为A ，80~89为B，70~79分为C，60~69分为D，小于60为E。求用switch语句编写的程序。

Answer 1

#include <stdio.h>

int main()

{

int score, m;

scanf("%d", &score);

while (score < 0 || score > 100){

printf("Error! Retry!\n");

scanf("%d", &score);

}

m= score / 10;

if (m>= 9)

printf("Grade is A!\n");

switch(m){

case 0: printf("Grade is E!\n"); break;

case 1: printf("Grade is E!\n"); break;

case 2: printf("Grade is E!\n"); break;

case 3: printf("Grade is E!\n"); break;

case 4: printf("Grade is E!\n"); break;

case 5: printf("Grade is E!\n"); break;

case 6: printf("Grade is D!\n"); break;

case 7: printf("Grade is C!\n"); break;

case 8: printf("Grade is B!\n"); break;

}

return 0;

}

扩展资料：

其他实现输出成绩等级‘A'、’B‘、'C'、‘D'、'E’。90分以上为A,80~89分为B，70~79分为C，60~69分为D，60分一下为E的方法：

#include <stdio.h>

int main()

{

int score;

scanf("%d", &score);

while (score < 0 || score >100){

printf("Error! Retry!\n");

scanf("%d", &score);

}

if (score < 60)

printf("Grade is E!\n");

else if (score >= 60 && score < 70)

printf("Grade is D!\n");

else if (score >= 70 && score < 80)

printf("Grade is C!\n");

else if (score >=80 && score < 90)

printf("Grade is B!\n");

else

printf("Grade is A!\n");

return 0;

}

Answer 2

#include<stdio.h>

int main()

{

int
a;

printf("输入你的成绩:");

scanf("%d",&a);

if(a>100||a<0)

{

printf("非法输入");

}

else

{

a=a/10;

switch(a)

{

case 10:
printf("A\n");break;

case 9: printf("A\n");break;

case 8: printf("B\n");break;

case 7: printf("C\n");break;

case 6: printf("D\n");break;

default:printf("E\n");break;

}

}

return
0;

}追问

谢谢

追答

第一次被采纳 好开心 处女采

本回答被提问者和网友采纳

Answer 3

#include <stdio.h>

int main()
{
printf("请输入分数:");
char szscore[2+1] = {0};
scanf("%s", &szscore);

printf("等级为:");
switch (*szscore) {
case '9' : printf("A\n"); break;
case '8' : printf("B\n"); break;
case '7' : printf("C\n"); break;
case '6' : printf("D\n"); break;
default : printf("E\n");
}
return 0;
}

希望能帮助到你！

Answer 4

用VLOOKUP函数对考核成绩划分等级