第3个回答 2013-11-07
/*'A':1000001 41 65
'B':1000010 42 66
'C':1000011 43 67
'D':1000100 44 68
'E':1000101 45 69
'F':1000110 46 70
'G':1000111 47 71
'H':1001000 48 72
'I':1001001 49 73
'J':1001010 4A 74
'K':1001011 4B 75
'L':1001100 4C 76
'M':1001101 4D 77
'N':1001110 4E 78
'O':1001111 4F 79
'P':1010000 50 80
'Q':1010001 51 81
'R':1010010 52 82
'S':1010011 53 83
'T':1010100 54 84
'U':1010101 55 85
'V':1010110 56 86
'W':1010111 57 87
'X':1011000 58 88
'Y':1011001 59 89
'Z':1011010 5A 90Press any key to continue*/#include <stdio.h>
#include <string.h>void fun(char *s,int n) { // 将整数n转换为二进制字符串s
int len,i = 0;
char ch;
while(n) {
s[i++] = n % 2 + '0';
n = n / 2;
}
s[i] = '\0';
len = strlen(s);
for(i = 0;i < len/2;i++) {
ch = s[i];
s[i] = s[len - i - 1];
s[len - i - 1] = ch;
}
}int main( ) {
char ch;
char s[20];
for(ch = 'A';ch <= 'Z';ch++) {
fun(s,ch);
printf("'%c':%s %0X %d\n",ch,s,ch,ch);
}
printf("\n");
return 0;
}