使用C语言编写猜数字问题

一.问题描述:
该游戏可以由程序随机产生或由用户输入四个0到9之间的数字,且不重复.玩游戏者通过游戏的提示输入8次来匹配上面所输入的数字.A表示位置正确且数字正确,B表示数字正确而位置不正确.
二.功能要求:
1.本游戏显示这样的菜单:
⑴随机产生数据
⑵用户输入数据
⑶退出游戏
2.游戏成功与否都能返回主菜单
三.算法提示:
1.数据结构:数组
2.用简单的程序设计方法
四.测试数据:
测试数据: 3792
第一次输入: 1234
0A2B
第二次输入: 5678
0A1B
第三次输入: 0867
0A1B
第四次输入: 9786
1A1B
第五次输入: 1794
2A0B

举报该问题

推荐答案 2009-07-14

<html>
<head>
<title>NumberGame</title>
<style type="text/css">

</style>
<script type="text/javascript">
var j=10;
var number =[0,0,0,0,0,0,0,0,0];
var numberv =[0,0,0,0,0,0,0,0,0];

function startgame(){
j=10;
window.status="number game";

document.getElementById("txt0").value = "";
document.getElementById("txt1").value = "";
document.getElementById("txt2").value = "";
document.getElementById("txt3").value = "";
document.getElementById("txt4").value = "";
document.getElementById("txt5").value = "";
document.getElementById("txt6").value = "";
document.getElementById("txt7").value = "";
document.getElementById("txt8").value = "";

for(i=0;i<9;i++){
document.getElementById("txt"+i).style.backgroundColor = '#ffffff';
}

document.getElementById("number0").innerHTML=Math.floor(Math.random()*10);
document.getElementById("number1").innerHTML=Math.floor(Math.random()*10);
document.getElementById("number2").innerHTML=Math.floor(Math.random()*10);
document.getElementById("number3").innerHTML=Math.floor(Math.random()*10);
document.getElementById("number4").innerHTML=Math.floor(Math.random()*10);
document.getElementById("number5").innerHTML=Math.floor(Math.random()*10);
document.getElementById("number6").innerHTML=Math.floor(Math.random()*10);
document.getElementById("number7").innerHTML=Math.floor(Math.random()*10);
document.getElementById("number8").innerHTML=Math.floor(Math.random()*10);

number[0]= document.getElementById("number0").innerHTML;
number[1]= document.getElementById("number1").innerHTML;
number[2]= document.getElementById("number2").innerHTML;
number[3]= document.getElementById("number3").innerHTML;
number[4]= document.getElementById("number4").innerHTML;
number[5]= document.getElementById("number5").innerHTML;
number[6]= document.getElementById("number6").innerHTML;
number[7]= document.getElementById("number7").innerHTML;
number[8]= document.getElementById("number8").innerHTML;
document.getElementById("start").disabled=true;
count();
}

function count(){

if(j>0){
j--;
document.getElementById('txt').innerHTML ='倒计时: '+j;
b = setTimeout("count();",1000);
}
else {
document.getElementById("number0").innerHTML = " ";
document.getElementById("number1").innerHTML = " ";
document.getElementById("number2").innerHTML = " ";
document.getElementById("number3").innerHTML = " ";
document.getElementById("number4").innerHTML = " ";
document.getElementById("number5").innerHTML = " ";
document.getElementById("number6").innerHTML = " ";
document.getElementById("number7").innerHTML = " ";
document.getElementById("number8").innerHTML = " ";

document.getElementById("txt0").disabled=false;
document.getElementById("txt1").disabled=false;
document.getElementById("txt2").disabled=false;
document.getElementById("txt3").disabled=false;
document.getElementById("txt4").disabled=false;
document.getElementById("txt5").disabled=false;
document.getElementById("txt6").disabled=false;
document.getElementById("txt7").disabled=false;
document.getElementById("txt8").disabled=false;
document.getElementById("submit").disabled=false;

}
}

function submit()
{
document.getElementById("number0").innerHTML = number[0];
document.getElementById("number1").innerHTML = number[1];
document.getElementById("number2").innerHTML = number[2];
document.getElementById("number3").innerHTML = number[3];
document.getElementById("number4").innerHTML = number[4];
document.getElementById("number5").innerHTML = number[5];
document.getElementById("number6").innerHTML = number[6];
document.getElementById("number7").innerHTML = number[7];
document.getElementById("number8").innerHTML = number[8];

numberv[0] = document.getElementById("txt0").value;
numberv[1] = document.getElementById("txt1").value;
numberv[2] = document.getElementById("txt2").value;
numberv[3] = document.getElementById("txt3").value;
numberv[4] = document.getElementById("txt4").value;
numberv[5] = document.getElementById("txt5").value;
numberv[6] = document.getElementById("txt6").value;
numberv[7] = document.getElementById("txt7").value;
numberv[8] = document.getElementById("txt8").value;
for(i=0;i<9;i++){
if(number[i]!=numberv[i]){
document.getElementById("txt"+i).style.backgroundColor = '#FF0000';
}

}

document.getElementById("start").disabled=false;
document.getElementById("submit").disabled=true;
}
</script>
</head>

<body>
<div id="txt"></div>
<div id="abc">
<table width="200" border="1" class="tab1">
<tr>
<td><span id="number0"></td>
<td><span id="number1"></td>
<td><span id="number2"></td>
<td><span id="number3"></td>
<td><span id="number4"></td>
<td><span id="number5"></td>
<td><span id="number6"></td>
<td><span id="number7"></td>
<td><span id="number8"></td>
</tr>
</table>
</div>
<div id="div2">
<table width="200" border="1" class="tab1">
<tr>
<td><input type="text" id="txt0" size="2" disabled/></td>
<td><input type="text" id="txt1" size="2" disabled/></td>
<td><input type="text" id="txt2" size="2" disabled/></td>
<td><input type="text" id="txt3" size="2" disabled/></td>
<td><input type="text" id="txt4" size="2" disabled/></td>
<td><input type="text" id="txt5" size="2" disabled/></td>
<td><input type="text" id="txt6" size="2" disabled/></td>
<td><input type="text" id="txt7" size="2" disabled/></td>
<td><input type="text" id="txt8" size="2" disabled/></td>
</tr>
</table>
<center><input id="start" type=button value="开始游戏" onClick="startgame();"></center>
<center><input id="submit" type=button value="提交 " onClick="submit();"></center>
</div>
</body>
</html>

这是js的猜数字，我这里木C语言的猜数字。呵呵。希望能有点用。

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其他回答

第1个回答 2009-07-15

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int aj[4],bj[4];

int operate1(int a)
{
aj[0]=a%10;
aj[1]=a/10%10;
aj[2]=a/100%10;
aj[3]=a/1000;
if(aj[0]!=aj[1]&&aj[0]!=aj[2]&&aj[0]!=aj[3]&&aj[1]!=aj[2]&&aj[1]!=aj[3]&&aj[2]!=aj[3]&&aj[0]!=0&&aj[1]!=0&&aj[2]!=0&&aj[3]!=0)
return 0;
else
return 1;
}

int operate2(int x)
{
if(x>=10000||x<=1000)
{
printf("Wrong data!\n");
return 1;
}
bj[0]=x%10;
bj[1]=x/10%10;
bj[2]=x/100%10;
bj[3]=x/1000;
return 0;
}
void main()
{
int a,flag=1,i,j,x,flag2=1;
int sum,num;
srand( (unsigned)time( NULL ) );
while(flag)
{
a=rand()%9000+1000;
flag=operate1(a);
}
while(num!=4)
{
flag2=1;
printf("Please input the number(1000--10000):\n");
scanf("%d",&x);
while(flag2)
{
flag2=operate2(x);
if(flag2==1)
{
printf("Please input the number again!(1000--10000):\n");
scanf("%d",&x);
}
}
sum=0;num=0;
for(i=0;i<4;i++)
{
for(j=0;j<4;j++)
{
if(aj[i]==bj[j])
{
sum++;
}
}
}
for(i=0,j=0;i<4,j<4;i++,j++)
{
if(aj[i]==bj[j])
{
num++;
}
}
printf("%dA%dB\n",sum,num);
}
if(num==4)
{
printf("You guess it!\n");
}
}

我这里有一个，稍稍修改，就能满足你的要求了！本回答被提问者采纳

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