ajax怎么提交整个form表单

Question

如题所述

Answer 1

$.fn.SetWebControls = function (data) {
var $id = $(this)
for (var key in data) {
var id = $id.find('#' + key);
if (id.attr('id')) {
var type = id.attr('type');
if (id.hasClass("input-datepicker")) {
type = "datepicker";
}
var value = $.trim(data[key]).replace(/ /g, '');
switch (type) {
case "checkbox":
if (value == 1) {
id.attr("checked", 'checked');
} else {
id.removeAttr("checked");
}
break;
case "select":
id.ComboBoxSetValue(value);
break;
case "selectTree":
id.ComboBoxTreeSetValue(value);
break;
case "datepicker":
id.val(formatDate(value, 'yyyy-MM-dd'));
break;
default:
id.val(value);
break;
}
}
}
}
var formdata= $("#form1").SetWebControls(); //获取整个表单的数据
var datavalue={name:"1",pass:"2"}
$("#form1").SetWebControls(datavalue); //将数据给整个表单