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解æ¹ç¨ç»y=xï¼y=x^2å¾äº¤ç¹åæ A(0,0)ï¼B(1,1)ï¼å æ¤äºé积åå¯ä»¥åæ累次积åï¼
\iint\limits_{D}xydxdy
=\int_0^1dx\int_{x^2}^xxydy
=\int_0^1\left(\frac{1}{2}x^3-\frac{1}{2}x^5\right)dx
=1/8-1/12
=1/24
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