如果e是
自然对数的底,那么
syms
x
y;
y=(exp(x)-exp(-x))/(exp(x)+exp(-x));
diff(y)
ans
=
1-(exp(x)-exp(-x))^2/(exp(x)+exp(-x))^2
如果e是某常量,那么
syms
x
y
e;
y
=(e^x-e^(-x))/(e^x+e^(-x));
diff(y)
ans
=
(e^x*log(e)+e^(-x)*log(e))/(e^x+e^(-x))-(e^x-e^(-x))/(e^x+e^(-x))^2*(e^x*log(e)-e^(-x)*log(e))本回答被提问者采纳