ajax访问后台，得到一个对象，我怎么以json格式返回到前台

Question

如题所述

Answer 1

public class JsonServlet extends HttpServlet {

private org.codehaus.jackson.map.ObjectMapper objectMapper = new org.codehaus.jackson.map.ObjectMapper();

@Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp)
throws ServletException, IOException {

resp.setContentType("application/json");

try {
User user = new User();
user.setId("1");
user.setName("user");
objectMapper.writeValue(resp.getOutputStream(), user);
} catch (Exception e) {
// TODO: handle exception
}

}

private static class User {

private String id;

private String name;

public String getId() {
return id;
}

public void setId(String id) {
this.id = id;
}

public String getName() {
return name;
}

public void setName(String name) {
this.name = name;
}

}
}

前台用jquery

$.post("", {}, function(user) {
alert(user.id, +" " + user.name);
}, "json");