比如:执行这个
for(i=0;i<=18;i++)
{
for(j=0;j<=14;j++)
{
if(qipan[i][j]=='X' &&qipan[i][j+1]=='X' &&qipan[i][j+2]=='X' &&qipan[i][j+3]=='X' &&qipan[i][j+4]=='X')
{
cout<<"黑子胜"<<endl;
}
}
}
如果都不满足再执行:
for(j=0;j<=18;j++)
{
for(i=0;i<=14;i++)
{
if(qipan[i][j]=='X' &&qipan[i+1][j]=='X' &&qipan[i+2][j]=='X' &&qipan[i+3][j]=='X' &&qipan[i+4][j]=='X')
{
cout<<"黑子胜"<<endl;
}
}
}
如何能让这两部分连接起来,新手求教