select* from T1 left join (select * from T2 where T2.id=T1.id)

Question

想要left join 后面查询关联 T1的数据怎么写
select * from #temp1 as T1
--数据量太大了想在第一个left join 中过滤数据 报无法绑定由多个部分组成的标识符 "T1.iSOsID"
left join (select * from (select * from T2 where left(cInvCode,1) = 'R' and SodId=T1. iSOsID)as T4
left join T5 on T4.POID = T5.POID
left join T6 on T4.ID = T6.iPOsID
left join T7 on T6.ID = T7.ID
) as T20

on T1.物料编码 = T20.cInvCode and T1.iSOsID = T20.SodId

Answer 1

select * from T1 left join T2 on T2.id=T1.id;
SQL LEFT JOIN 关键字
LEFT JOIN 关键字会从左表 (table_name1) 那里返回所有的行，即使在右表 (table_name2) 中没有匹配的行。
LEFT JOIN 关键字语法
SELECT column_name(s)
FROM table_name1
LEFT JOIN table_name2
ON table_name1.column_name=table_name2.column_name

注释：在某些数据库中， LEFT JOIN 称为 LEFT OUTER JOIN。

Answer 2

select * from t1 left join t2 on t1.id=t2.id