C语言编程：从键盘输入任意个整数，输入-1时结束，分别统计其中奇数和偶数的个数

Question

如题所述

Answer 1

#include "stdio.h"
int main()
{
   int count1=0,count2=0,i;
   while(1)
   {
       scanf("%d",&i);
       if(i==-1)
          break;
       else if(i%2==0)
         count1++;
       else if(i%2==1)
         count2++;
    }
    printf("奇数共有%d个，偶数共有%d个.\n",count2,count1);
}

Answer 2

#include<stdio.h>
int main()
{
    int even,odd,n; 
    even=odd=0;
    while(scanf("%d",&n)!=EOF)
    {
        if(n==-1) break; 
        if(n%2==0) even++; 
        else odd++; 
    }
    printf("偶数=%d个  奇数=%d个\n",even,odd); 
    return 0; 
}

Answer 3

负数也有奇偶之分，输入的-1也是奇数，0也是特殊偶数

Answer 4

#include<stdio.h>
int main()
{
int i;
int a=0,b=0;
scanf("%d",&i);
while(i!=-1)
{
if(i%2==0)a++;
else b++;
scanf("%d",&i);
}

printf("奇数有%d个，偶数有%d个\n",b,a);

}