,因式分解 (-2)的99次方+(-2)的100次方

Question

如题所述

Answer 1

(-2)^99+(-2)^100
= (-2)^99x1+(-2)^99x(-2)
=(-2)^99x(-2+1)
=(-2)^99x(-1)
=2^99

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(x-y+z)(x+y-z)-（y-z-x)（y+z-x)

Answer 2

(-2)的99次方+(-2)的100次方
=(-2)的99次方*(1-2)
=2^99追问

为啥*(1-2)

追答

(-2)的100次方

=(-2)的99次方x(-2)

追问

(x-y+z)(x+y-z)-（y-z-x)（y+z-x)

追答

(x-y+z)(x+y-z)-（y-z-x)（y+z-x)

追问

答这题加200分

追答

(x-y+z)(x+y-z)-（y-z-x)（y+z-x)
=[x-(y-z)][x+(y-z)]-[(y-x)-z][(y-x)+z]
=x²-(y-z)²-[(y-x)²-z²]
=x²-y²+2yz-z²-(y²-2xy+x²-z²)
=x²-y²+2yz-z²-y²+2xy-x²+z²
=-2y²+2yz+2xy
=-2y(y-z-z)

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