10i1=i-i2.........(1)
(2+3+5)i1-3i2-5i=0ï¼10i1-3i2=5iï¼å°(1)ä»£å ¥ï¼i=-i2.........(2)
12=6i+2i1+4i2ï¼å°(2)ä»£å ¥ï¼6=i1-i2........(3)
u=(5+6)i-5i1=12-(3+4)i2+3i1ï¼12=11i-8i1+7i2=-8i1-4i2ï¼-3=2i1+i2.........(4)
(3)+(4) 3=3i1ï¼i1=1Aï¼i2=-5Aï¼i=5Aã