<style type="text/css">
<!--
iewrap1{height:30px;}
-->
</style>
<title>单击链接显示菜单</title>
<script language="javascript">
var index=100;
function dropit2(whichone)
{
if(window.themenu&&themenu.id!=whichone.id)
{themenu.style.visibility="hidden";
themenu=whichone;}
if(document.all)
{
<!--设置弹出菜单横想距离-->
themenu.style.left=document.body.scrollLeft+event.clientX-event.offsetX+5;
<!--设置弹出菜单的纵向距离-->
themenu.style.top=document.body.scrollTop+event.clientY-event.offsetY+10;
if(themenu.style.visibility=="hidden")
{
="visible";
themenu.style.index=index++;
}
else
{ hidemenu()}
}
}
</script>
</head>
<body>
<div id="back" onMouseOut="dripit2()" style="position:absolute;top:166px;left:353px;width:160;height:41px;z-index:1px;visibility:visible;">
<span id="menubar" onMouseOver="themenu.style.visibility='visible'">[javascript中文网]</span>
<div border=1 id="themenu" style="position:absolute;top:15px;left:0px;width:66px;height:10px;z-index:2px;visibility:hidden;">
<script language="javascript">
var menu=new Array();
<!--设置弹出菜单的选项各名称及颜色-->
menu[0]='<a href="#"><font color="#ffff00">javascript课程</font></a><br>'
<!--设置菜单的选项各名称几颜色-->
menu[1]='<a href="#"><font color="#ffff00">javascript软件</font></a><br>'
<!--设置菜单的选项各名称几颜色-->
menu[2]='<a href="#"><font color="#ffff00">javascript论坛</font></a><br>'
if(document.all)
{
dropmenu0.style.padding="4px";
for(i=0;i<menu;i++)
document.write(menu[i]);
}
</script>
</div>
</div>
</body>
</html>
哪位学习JAVASCRIP的好手，帮帮忙，你们也可以提供一个好的JAVASCRIP给我一个看看，有程序简单效果好的吗：）谢谢