求4sin20+tan20的值

如题所述

第1个回答  2012-04-11
tan20°+4sin20°
=(sin20°+2sin40°)/cos20°
=(sin20°+sin40°+sin40°)/cos20°
=(2sin30°cos10°+sin40°)/cos20°
=(cos10°+sin40°)/cos20°
=(sin80°+sin40°)/cos20°
=2sin60°cos20°/cos20°=2sin60°
=根号3本回答被提问者采纳
第2个回答  2012-04-11
√3