第1个回答 2006-07-08
#include "stdio.h"
main()
{int i,j;
char a[10],t
for (i=0;i<10;i++)
{printf("请输入第%d个字符",i);
scanf("%c",&a[i]);}
for (i=0;i<10;i++)
for (j=0;j<10-i;j++)
if (a[j]<a[j+1])
{t=a[j+1];
a[j+1]=a[j];
a[j]=t;
}
for (i=1;i<10;i++)
printf("%c",a[i]);
}
第2个回答 2006-07-09
dim i,j,k as integer;
dim a[10] as integer
for i=1 to 10
a[i]=i
next i
for i=0 to 9
for j=0 to i
if a[i]<a[j] then
{
k=a[i];
a[i]=a[j];
a[j]=k;
}
next j
next i
第3个回答 2006-07-08
dim i,j,k as integer;
dim a[10] as integer
for i=1 to 10
a[i]=i
next i
for i=0 to 9
for j=0 to i
if a[i]<a[j] then
{
k=a[i];
a[i]=a[j];
a[j]=k;
}
next j
next i